Home Back
Chapter 1: Introduction



Problem 1.3:

The pressure and temperature at a certain point in an air flow are 130 kPa and 30oC, respectively. Find the air density at this point in kg/m3 and lbm/ft3.

Solution:

Given \( p=130\,\text{kPa}=130\times10^{3}\,\text{Pa}, T=30^{\circ}\text{C}=30+273=303\,\text{K}. \)

The density can be calculated using ideal gas law as,

$$ \boxed{\rho=\frac{p}{R\,T}=\frac{130\times10^{3}}{287\times303}=1.495\,\text{kg/m}^{3}}\ . $$

The density in \( \text{lbm/ft}^{3} \) can be calculated using the following conversions \( 1\,\text{kg}=2.2046\,\text{lbm} \), \( 1\,\text{m}=3.2808\,\text{ft} \). Therefore in \( \text{lbm/ft}^{3} \),

$$ \rho=1.495\,\text{kg/m}^{3}=1.495\times2.2046/3.2808^{3}\,\text{lbm/ft}^{3} $$ $$ \boxed{\rho=0.09333\,\text{lbm/ft}^{3}}\ . $$



--- Ad ---

---


For further details, please contact me at:
mail.spbhat@gmail.com
If you observe any error or want to provide me with feedback, please don't hesitate to contact me.

Thanks,
Sourabh Bhat